In this discussion, you will use the students’ posters to solidify understandings of adding negative and positive numbers. Ask the students to explain their strategies. At first the students will struggle to explain how they know the right answer, and they will probably use imprecise language. During this time, teacher and students can start using more formal vocabulary to help clarify explanations. In this discussion, your students will to use key terminology like opposite, absolute value, and additive inverse. Using the terms in this meaningful and relevant context is intended to deepen their understanding.
Using the sample posters in the previous section, the following guide is ordered roughly by level of complexity, beginning with the most intuitive example of a and b as both positive is first. Beyond these five samples, students can consider other interesting configurations in which a = b.
Discussable math from Poster A (a and b are both positive and a > b)
This case is familiar to students, but they may not have formalized their understandings. Here are three generalizations:
- (a + b) is to the right of both a and b because both a and b are positive.
- (a – b) is positive and less than a because b is positive and less than a (think of 5 – 3 = 2 as an example).
- (b – a) is negative because we are subtracting a larger positive number from b (for example 3 – 5 = -2).
Discussable math from Poster B (a and b are both negative with a < b)
- This might be the most challenging poster for students to explain.
- In this poster, we can see that a + b is the farthest to the left because a negative number plus another negative number is negative. Students might say a + b is “a larger negative number.” This can be re-stated as (a + b) has a larger absolute value.
- (a – b) is located between a and 0. Students might notice that they can re-write subtraction as addition: (a – b) = a + (-b). Since b is negative, the opposite of b, that is, -b, is positive so a + (-b) is to the right of a.
- (b – a) is to the right of 0--it is positive. One way to explain this is that b – a = b + (-a). But remember, since a is negative, -a is positive. Also, since a is farther from zero (formally written in terms of absolute values, |a| > |b|) this tells us (b – a) will be positive.
Discussable math from Poster C (a and b are opposite signs and equally distant from zero)
- Students might like the symmetry in this poster.
- In this case, we see that a + b = 0. This tells is that a = -b and b = -a. In other words, a and b are opposites. This is a special situation--adding two numbers and getting zero means the numbers are additive inverses of each other. (You could highlight how the additive inverse plays a major role in solving algebraic equations like x + 4 = 12).
- We also see that (a – b) is less than a. This makes sense because b is positive and a – b = a + (-b).
- Finally, (b – a) is positive and greater than (to the right of) b because (b – a) = b + (-a) and, don’t forget, -a is positive.
Discussable math from Poster D (a and b are opposites but are not equally distant from zero; a > b)
- Here we can see that (a + b) is between a and b. This is because a and b have opposite signs. However, we can tell that a ≠ -b because a + b ≠ 0 (as in Poster C).
- (b – a) is less than b because (b – a) = b + (-a) and adding the opposite of a to b has the same effect as adding two negative numbers.
- Finally, (a – b) is greater than a because b < 0 and a – b = a + (-b). Since b < 0, -b > 0 and a + (-b) is the same as adding two positive numbers.
Discussable math from Poster E (One of the numbers is 0)
- Note that in this picture, a, (a + b) and (a – b) are all at the same point on the number line.
- In this poster, b = 0. When b is zero, a + b = a + 0 = a. 0 is called the additive identity and it plays an important role throughout math.
- (a – b) is also equal to a because a – 0 = a.
- Finally, (b – a) = 0 – a = -a. That is, (b – a) is the same distance from 0 as a, but has the opposite sign.
Looking across and synthesizing
You can raise one final discussion point: (b – a) and (a – b) are always on opposite sides of zero and the same distance from zero. In symbols this means (a – b) = -(b – a). But don’t worry too much about having your students use symbols for this expression. Instead, point out that if you know 8 – 3 = 5, then 3 – 8 is the opposite, or -5. This approach provides a nice way to make signed addition and subtraction easier.